To get a C in history, Nandan must average 74 on four tests. Scores on the first three tests were 69, 75, and 60. What is the lowest score that Nandan can get on the last test and still receive a C?

Question

To get a C in history, Nandan must average 74 on four tests. Scores on the first three tests were 69, 75, and 60. What is the lowest score that Nandan can get on the last test and still receive a C?

Answer 1

69 + 75 + 60 = 204

400 * 0.74 = 296

296 - 204 = ?

Answer 2

Well, it seems like Nandan must really be a history buff to want to aim for a C! But let's crunch some numbers and see what we can come up with.

To find out the lowest score Nandan can get on the last test, let's first calculate the total score of the first three tests. Adding up 69+75+60, we get a total of 204.

Now, let's subtract this total from the score needed for a C, which is 74 multiplied by 4 (296 - 204 = 92).

So, Nandan needs to score a minimum of 92 on the last test to achieve a C.

Answer 3

To find out the lowest score Nandan can get on the last test and still receive a C, we need to calculate the average of the four tests.

Let's denote the lowest score that Nandan can get on the last test as "x."

To calculate the average, we need to sum up all the test scores and then divide by the number of tests:

(69 + 75 + 60 + x) / 4 = 74

Now, let's solve the equation for x:

(69 + 75 + 60 + x) = 74 * 4

(204 + x) = 296

Subtracting 204 from both sides:

x = 296 - 204

x = 92

Therefore, the lowest score that Nandan can get on the last test and still receive a C is 92.

Answer 4

To find the lowest score Nandan can get on the last test and still receive a C, we need to determine the minimum average score required.

Since Nandan's target grade is a C, which is usually around 70-79, let's assume the target average score is 74, as mentioned in the question.

To determine Nandan's average score, we can use the formula:

Average Score = (Sum of Scores)/(Number of Tests)

Given that Nandan has already taken three tests and has scored 69, 75, and 60 on them, we can substitute these scores into the formula to calculate the sum:

Sum of Scores = 69 + 75 + 60 = 204

Now, since Nandan must average 74 on four tests to receive a C, we can use the rearranged formula to determine the lowest score:

Lowest Score = (Target Average * Number of Tests) - Sum of Scores

Lowest Score = (74 * 4) - 204

Lowest Score = 296 - 204

Lowest Score = 92

Therefore, the lowest score that Nandan can get on the last test and still receive a C is 92.