Suppose you have two 100- graduated cylinders. In each cylinder there is 44.0 of water. You also have two cubes: One is lead, and the other is aluminum. Each cube measures 1.5 on each side.

After you carefully lower each cube into the water of its own cylinder, what will the new water level be in each of the cylinders? Assume that cubes are totally emerged in the water.

Density of Lead= 11.3 g/ml or g/cm^3
Density of Aluminum= 2.70 g/ml or g/cm^3

I just need help on the set up of the equation.

If the length of the cubes are 1.5 WHAT on a side (I'll assume cm), then volume is 1.5^3 cc and that added to 44.0 will be the new volume in each graduated cylinder.

Don't get sucked into thinking the volumes will be different because the densities are so much different. Volume is determined by the length of each cube and not by the density.

Thank You SO MUCH!!!

To find the new water level in each cylinder after lowering the cubes into the water, we need to consider the displacement of water caused by each cube.

The volume of an object can be calculated by multiplying its length, width, and height. Since each cube measures 1.5 cm on each side, the volume of each cube is:

Volume of cube = length × width × height
= 1.5 cm × 1.5 cm × 1.5 cm
= 3.375 cm^3

Now, let's calculate the mass of each cube. The mass of an object can be calculated by multiplying its volume and density. Given the densities of lead and aluminum, we can calculate the mass of each cube as follows:

Mass of lead cube = Volume of cube × Density of lead
= 3.375 cm^3 × 11.3 g/cm^3
≈ 38.138 g

Mass of aluminum cube = Volume of cube × Density of aluminum
= 3.375 cm^3 × 2.70 g/cm^3
≈ 9.1125 g

The total displacement of water caused by each cube will be equal to the volume of each cube. Therefore, the new water level in each cylinder can be calculated by dividing the volume of each cube by the cross-sectional area of the graduated cylinders.

The cross-sectional area of a graduated cylinder can be calculated using the formula:

Area = π × (radius)^2

Since the diameter of each graduated cylinder is 100 cm, the radius is 50 cm. Therefore, the area of each graduated cylinder is:

Area = π × (50 cm)^2
= 2500π cm^2

Now, let's calculate the new water level in each cylinder:

New water level in lead cylinder = Volume of lead cube / Area of graduated cylinder
= 3.375 cm^3 / (2500π cm^2)
≈ 0.000429 cm

New water level in aluminum cylinder = Volume of aluminum cube / Area of graduated cylinder
= 3.375 cm^3 / (2500π cm^2)
≈ 0.000429 cm

Therefore, the new water level in each graduated cylinder, after lowering the cubes into the water, is approximately 0.000429 cm.