how would you solve:
Find the sum of the first 12 terms to the earest hundreth 6 + 2 + 2/3 +...
looks like a geometric series with
a = 6 , r = 1/3
sum12 = 6((1/3)^12 - 1)/(1/3 - 1)
= 6(1/531441 - 1)/(-2/3)
= 8.999983
= 9.00 correct to the nearest hundredth