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March 29, 2015

March 29, 2015

Posted by **Anonymous** on Saturday, September 3, 2011 at 3:57pm.

Sec^-1(-2)

sec^-1(-sqrt2)

Cos^-1((-sqrt3)/2)

Tan^-1(-sqrt3)

Could someone explain how to get the answer as well please.

- trig -
**Henry**, Monday, September 5, 2011 at 4:13pmTo limit the results to only one answer, the range must be limited to a

value between 0 and 180 degrees:

0 < A < 180.

secA = 1/cosA = -2,

cosA = -1/2,

A = 120 deg.

secA = 1/cosA = -sqrt2,

cosA = -1/sqrt2,

A = 135 deg.

cosA = -(sqrt3)/2,

A = 150 deg.

tanA = -sqrt3,

A = -60 deg.,CW = -60 + 180 = 120 deg.

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