h(0.5) if h(x) = 6-2x^3
So I set it up as
6 - 2(0.5^3) correct? That way only the (0.5) is being cubed, and THEN multiplied by 2? Or does it mean to cube the entire product? Such as (2 x 0.5)^3?
Ugh simple things like this always get me! I can solve it easily, just need help setting it up! thanks!
cube the *.5 (.125) then multipy by 2
Thank you! my final answer is 5.75, correct?
yep. if the question is 6-(2x)^3 then you need to cube 2x but in your question it's 6-2x^3 without the brackets so u only need to cube x.
To evaluate h(0.5) using the given function h(x) = 6 - 2x^3, you need to substitute the value 0.5 in place of x.
You set it up correctly as 6 - 2(0.5^3). Let's break it down step by step:
1. First, calculate the value inside parentheses: 0.5^3.
Cubing 0.5 means multiplying it by itself three times:
0.5^3 = 0.5 * 0.5 * 0.5 = 0.125.
2. Next, substitute the value you obtained in step 1 into the expression:
6 - 2(0.125).
3. Multiply 2 by 0.125:
6 - 0.25.
4. Finally, subtract 0.25 from 6:
h(0.5) = 5.75.
So, h(0.5) is equal to 5.75.