Posted by squires on Friday, September 2, 2011 at 5:07pm.
Let u = x direction velocity (i) and v = y direction (j) velocity
Xo = 0
Yo = 4
Uo = +2
Vo = 0
Ax = -2
Ay = -2
u = Uo + Ax t
u = 2 - 2 t
x = Xo + Uo t +(1/2) Ax t^2
x = 2 t - t^2
y = Yo + Vo t + (1/2) Ay t^2
y = 4 - t^2
so
y = 0 when t = 2
u = 0 when t = 1
Thank you very much.. i understand it...it crosses the x-axis when the y point is =o, and is parallel to the y- axis when the vector in the x direction aka the slope is = to 0 =]
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