Posted by amy on Friday, September 2, 2011 at 12:48am.
Assuming they travel in one-dimension we can use the x(t)= vt+1/2 at^2.
The slower boy will travel a distance X and the faster boy will travel a distance 100-X because X will be the meeting point. And there is no acceleration involved, so the equation will look like x=5t and 100-x = 7t. Solve for T on both side because they meet at the same time so both t will equal and the rest is just simple algebra
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