Posted by **Alice** on Thursday, September 1, 2011 at 12:30pm.

A jogger leaves home and runs at a constant speed of 4 miles per hour. Nine minutes later, a bicyclist follows along the same route at a constant speed of 15 miles per hour. Find the bicyclist's travel time needed to catch the jogger.

- algebra -
**Reiny**, Thursday, September 1, 2011 at 4:34pm
9 minutes = .15 hour

they both went the same distance.

bikers time ---- t hrs

jogger's time -- t+.15

15t = 4(t+.15)

15t = 4t + .6

11t = .6

t = .0545 hrs or 3.2727 minutes or 3 min and 16.4 seconds

- algebra -
**jennifer**, Tuesday, August 28, 2012 at 8:53am
3/11 minutes

- algebra -
**Anonymous**, Wednesday, December 14, 2016 at 8:46pm
Junior drove 55.6 miles then he drove 42 1/5 miles. How many miles did he drove in all??

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