Posted by Alice on Thursday, September 1, 2011 at 12:30pm.
A jogger leaves home and runs at a constant speed of 4 miles per hour. Nine minutes later, a bicyclist follows along the same route at a constant speed of 15 miles per hour. Find the bicyclist's travel time needed to catch the jogger.

algebra  Reiny, Thursday, September 1, 2011 at 4:34pm
9 minutes = .15 hour
they both went the same distance.
bikers time  t hrs
jogger's time  t+.15
15t = 4(t+.15)
15t = 4t + .6
11t = .6
t = .0545 hrs or 3.2727 minutes or 3 min and 16.4 seconds

algebra  jennifer, Tuesday, August 28, 2012 at 8:53am
3/11 minutes

algebra  Anonymous, Wednesday, December 14, 2016 at 8:46pm
Junior drove 55.6 miles then he drove 42 1/5 miles. How many miles did he drove in all??
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