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September 16, 2014

September 16, 2014

Posted by **cody** on Wednesday, August 31, 2011 at 6:58pm.

- precalculus -
**Reiny**, Wednesday, August 31, 2011 at 8:44pmj = k(h^2)(a^(1/3)/s

when h is doubled , a multiplied by 8, s multiplied by 4

j_{2}= k (4h^2)(2a^(1/3)/(4s)

j_{2}/ j = [ k (4h^2)(2a^(1/3)/(4s) ] / [k(h^2)(a^(1/3)/s]

= 4(2)/2 = 2

the value of j will double

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