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September 3, 2014

September 3, 2014

Posted by **Heather** on Wednesday, August 31, 2011 at 6:34pm.

- Intermediate Algebra -
**Reiny**, Wednesday, August 31, 2011 at 8:47pmlet the amount of 90% antifreeze to be added be x gallons

.9x + .3(100) = .8(100+x)

times 10

9x + 3(100) = 8(100+x)

9x+300 = 800+8x

x = 500

500 gallons of the 90% must be added.

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