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Calculus

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Infinite series question.

an=2+(0.99)^n

Converge or Diverge?

  • Calculus - ,

    look at .99^n

    .99^5 = .95099049.....
    .99^250 = .08105...

    as n ---> ∞ the value of .99^n approaches zero
    so you are left with
    2 + 0

    so it converges to the value of 2

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