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April 20, 2014

April 20, 2014

Posted by **Mike** on Wednesday, August 31, 2011 at 6:26pm.

an=2+(0.99)^n

Converge or Diverge?

- Calculus -
**Reiny**, Wednesday, August 31, 2011 at 8:51pmlook at .99^n

.99^5 = .95099049.....

.99^250 = .08105...

as n ---> ∞ the value of .99^n approaches zero

so you are left with

2 + 0

so it converges to the value of 2

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