Posted by Stoichiometry on Wednesday, August 31, 2011 at 11:33am.
Another stoichiometry problem BUT there is a short cut that saves a lot of time; however, the shortcut is not taught, to my knowledge, anymore.
Here is the short cut.
grams Fe in the ore = grams Fe2O3 x (2*atomic mass Fe/molar mass Fe2O3) = ?
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