Posted by jordy on Wednesday, August 31, 2011 at 10:10am.
Isn't this the point of the Rydberg equation?
1/lambda= R(1/n^2 -1/m^2)
but E=plancksConstant*c/lambda
so E=plancksconstant*c * R (1/n^2-1/m^2)
c is the speed of light, R is the Rydberg constant, m,m are the two states.
What is neat about this method is it can be 'extended' to other atoms, by the multiplication Z^2 where Z is the atomic number.
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