Wednesday

August 27, 2014

August 27, 2014

Posted by **Aria** on Wednesday, August 31, 2011 at 4:04am.

f(x)=x^2-9x+15 find x and y intercepts

-9+square root of 21/2,0

-9-square root of 21/2,0

x^2-x+3=0 solve and find x-intercepts

(1+square root of -11/2,0)

(-1-square root of -11/2,0)

- Algebra -
**Reiny**, Wednesday, August 31, 2011 at 7:44amfor ax^2 + bx + c = 0,

x = (-b ± √(b^2 - 4ac) )/(2a)

so for yours, for the x-intercepts

x = (+9 ± √(81-4(1)(15))/2

= (9 ± √21)/2

for the y-intercept, let x=0

f(0) = 0-9+15 = 15

for the second:

x-intercept: (1 + √-11)/2 , (you had 1 + √-11/2 ---> only the last term was divided by 2 )

y-intercept : 3

- Algebra -
**Aria**, Wednesday, August 31, 2011 at 6:19pmHi

I don't understand how you are getting the y intercept. I am so confused about which numbers are solutions, vertex, x-intercepts, y-intercepts etc.

Can you write out an example of an equation and how you get each number from a formula. I have been in this class for nine weeks and with all the information I have at my disposal I still am confused.

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