Homework Help: physics

Posted by mae on Tuesday, August 30, 2011 at 8:27pm.

A ball is thrown upward from the top of a 24.4-m-tall building. The ball's initial speed is 12 m/s. At the same instant, a person is running on the ground at a distance of 30.2 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the building?
PLEASE HELP!!!!!!! :)

physics - bobpursley, Tuesday, August 30, 2011 at 8:31pm
find the time it takes the ball to get to the bottom
Hf=hi+vi*t-1/2 g t^2
0=24.4+12*t-4.8 t^2
use the quadratic equation to find time of fall t.

Now, how fast does the person run? v=30.2/timet

Answer this Question

Related Questions

Physics - A ball is thrown upward from the top of a 24.6 m tall building. The ...
physic - A ball is thrown upward from the top of a 24.4 m tall building. The ...
Physics - A ball is thrown upward from the top of a 50.0 m tall building. The ...
physics - A ball is thrown upward from the top of a 40.0 m tall ...
physics - A ball is thrown upward with an initial velocity of 6.0m/s by someone ...
physics - A ball is thrown upward from the top of a 27.0-m-tall building. The ...
physics - A ball is thrown from the top of a building upward at an angle of 66 &...
Physics - The ball is thrown upward with a speed of 38.0m/s from the top of a ...
Math: Word Problem - A ball is thrown upward from the top of a building which is...
physics - Assume acceleration due to gravity=10 m/s. A ball is thrown ...

For Further Reading

First Name:
School Subject:
Answer: