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A ball is thrown upward from the top of a 24.4-m-tall building. The ball's initial speed is 12 m/s. At the same instant, a person is running on the ground at a distance of 30.2 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the building?
PLEASE HELP!!!!!!! :)

  • physics -

    find the time it takes the ball to get to the bottom
    Hf=hi+vi*t-1/2 g t^2
    0=24.4+12*t-4.8 t^2
    use the quadratic equation to find time of fall t.

    Now, how fast does the person run? v=30.2/timet

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