Posted by **Joe** on Monday, August 29, 2011 at 6:57pm.

select T.branch_name

from branch T, branch S

where T.assets > S.assets and S.branch_city = "Brooklyn"

Write an efficient relational algebra

expression that is equivalent to this query.

Here is my answer:

á T.branch_name (T.assets > S.assets v S.branch_city = “Brooklyn”) (branch)

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