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April 16, 2014

April 16, 2014

Posted by **Ruby** on Monday, August 29, 2011 at 8:27am.

1.A metal gutter open at the tops and ends, is bent up from material 30 cm wide to form a rectangular cross section.

a) If the base of the gutter is x cm wide, find the height of the gutter.

b)Show that the area of the gutter cross section is given by A = 15x - x^2/2.

Thanks.

- mathematics -
**Reiny**, Monday, August 29, 2011 at 8:42amMake a sketch of the cross-section

I would assume the you are bending the 30 cm wide piece so that the two sides of the gutter are of equal height.

then if the base is x cm, then the height must be (30-x)/2 or 15 - x/2 or 15 - (1/2)x

Area = base x height

= x(15 - x/2) = 15x - x^2/2

- mathematics -
**Ruby**, Monday, August 29, 2011 at 8:53amthank you very much for your help.

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