Posted by **TRACI** on Sunday, August 28, 2011 at 9:30pm.

the perimeter of a triangle is 51 centimeters, the longest side is 1 centimeter less than the sum of the other two sides. twice the shortest is 11 centimeters less than the longest side. find the lengths of each side of the triangle.

- ALGEBRA II -
**bobpursley**, Sunday, August 28, 2011 at 9:45pm
L=S1+S2-1

2*S1+11=L

L+S1+S2=51

rearranging these

S1+S2-L=1

2S1 -L=-11

S2+S2+L=51

add the two last equations

2S1+S2=40

subtract the first from the second

S1-S2=-12

add these two equations

3S1=28

S1=7

can you take if from here?

- ALGEBRA II ( inaccuracy -
**Mgraph**, Sunday, August 28, 2011 at 10:09pm
... add the two last eq.

3S1+S2=28

...

4S1=28

- ALGEBRA II -
**bobpursley**, Sunday, August 28, 2011 at 10:13pm
Thanks. I typoed and did not catch it.

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