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March 26, 2017

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write the slope-intercept equation for the line that passes through (-8,-11) and is perpendicular to -2x-7y=-14

  • algebra - ,

    Lines perpendicular to:
    -2x-7y=-14
    would have the form:
    -7x+2y=k
    where k is a constant to be determined using the point (-8,-11).
    Substitute x=-8, y=-11, we get
    -7(-8)+2(-11)=k
    =>
    k=34
    The line is therefore
    -7x+2y=34

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