Posted by **babygirl** on Sunday, August 28, 2011 at 7:21pm.

write the slope-intercept equation for the line that passes through (-8,-11) and is perpendicular to -2x-7y=-14

- algebra -
**MathMate**, Sunday, August 28, 2011 at 9:09pm
Lines perpendicular to:

-2x-7y=-14

would have the form:

-7x+2y=k

where k is a constant to be determined using the point (-8,-11).

Substitute x=-8, y=-11, we get

-7(-8)+2(-11)=k

=>

k=34

The line is therefore

-7x+2y=34

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