Friday

September 19, 2014

September 19, 2014

Posted by **Preston** on Sunday, August 28, 2011 at 6:46am.

i have my triangle graphed in the fourth quadrant but I'm getting confused because of the negatives...

- math -
**Reiny**, Sunday, August 28, 2011 at 8:35amcscØ = -3 , so sinØ = -1/3

the sine is negative in III and IV

cosine is positive in I and IV

so you are correct to say that Ø is in IV

make yourself familiar with the CAST rule, here is an explanation for it

http://www.mathsrevision.net/alevel/pages.php?page=36

So your triangle in IV should be a 1-√8 -3 triangle

sinØ = -1/3 , cscØ = -3 (that was the given)

cos = √8/3 , secØ = 3/√8

tanØ = -1/√8 , cotØ = -√8

(Your textbook answer might have written the √8 as 2√2 )

**Answer this Question**

**Related Questions**

Trigonometric Functions - Determine the Value of all six trigonometric functions...

trig - If sin theta is equal to 5/13 and theta is an angle in quadrant II find ...

trig - If theta is the measure of an angle in standard position with the given ...

Math - 1. Let (-7, 4) be a point on the terminal side of (theta). Find the exact...

Trigonometry - I don't understand how I'm supposed set the problem up or what ...

math - Hi ! Here is my question: The pythagorean theorem gives the relationships...

math (trig) - if cos 2 theta = -(1/3) and theta is in Quadrant 2, find sin theta...

Trigonometry - Thank you STEVE!!!!! Suppose that Cos (theta) = 1/square root 2 ...

trig - Let (theta) be an angle in quadrant II such that csc(theta)=8/5 Find the ...

trig - Let (theta) be an angle in quadrant II such that csc(theta)=8/5 Find the ...