Monday

April 21, 2014

April 21, 2014

Posted by **Preston** on Sunday, August 28, 2011 at 6:46am.

i have my triangle graphed in the fourth quadrant but I'm getting confused because of the negatives...

- math -
**Reiny**, Sunday, August 28, 2011 at 8:35amcscØ = -3 , so sinØ = -1/3

the sine is negative in III and IV

cosine is positive in I and IV

so you are correct to say that Ø is in IV

make yourself familiar with the CAST rule, here is an explanation for it

http://www.mathsrevision.net/alevel/pages.php?page=36

So your triangle in IV should be a 1-√8 -3 triangle

sinØ = -1/3 , cscØ = -3 (that was the given)

cos = √8/3 , secØ = 3/√8

tanØ = -1/√8 , cotØ = -√8

(Your textbook answer might have written the √8 as 2√2 )

**Related Questions**

trig - If theta is the measure of an angle in standard position with the given ...

Precalculus check answers help! - 1.) Find an expression equivalent to sec theta...

Precalculus check answers help! - 1.) Find an expression equivalent to sec theta...

Math - 1. Let (-7, 4) be a point on the terminal side of (theta). Find the exact...

trig - If sin theta is equal to 5/13 and theta is an angle in quadrant II find ...

math - How do I solve a this problem under the given conditions? cos(2[theta]) ...

Math - Let (3,-2) be a point on the terminal side of theta. Find cos theta, csc ...

Calculus - I wanted to confirm that I solved these problems correctly (we had to...

Precalculus(NEED HELP ASAP PLEASE!!) - cot(theta)= 3 pi < theta < 3pi/2 ...

trig - Given Tangent theta = -5 on 4 and cos theta >0, find sine theta and ...