Posted by Laynette on Friday, August 26, 2011 at 10:04pm.
1) 300 is two deviations of 50 away from 200, so the standard score is 2.
2) You need to look at a normal distribution for this. A quick google search should help you just fine. Or, possibly, you were provided one in class.
From such a table, you can see that being two deviations away from the middle amounts to 34.13% + 13.59% = 47.72%
3) You just take 47.72% 9which is the distance from the middle to 300) and add 50% (which is everyone below the middle). You get 97.72%
1. Z (a standard score) = (score-mean/SD)
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to the Z scores.
Percentile rank is the proportion below or equal to a particular score.
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