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September 4, 2015
Posted by **University of Phoenix** on Friday, August 26, 2011 at 9:40pm.

- Math 116 -
**Henry**, Saturday, August 27, 2011 at 9:43pmV(h,k)) = V(3,4), P(2,3).

Y = a(x-h)^2 + k.

P(2,3)

Y = a(2-3)^2 + 4 = 3,

a + 4 = 3,

a = 3 - 4 = -1.

Y = -1(x-3)^2 + 4, Vertex form.

Y = -x^2 + 6x - 5. Standard form.

-x^2 + 6x - 5 = 0,

Solve using Quadratic Formula and get:

X = 1, and X = 5.

P1(-2,-21)

P2(2,3).