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July 30, 2014

July 30, 2014

Posted by **BC** on Friday, August 26, 2011 at 7:13pm.

- algebra -
**bobpursley**, Friday, August 26, 2011 at 7:49pmdistancecar= 60*t/60=t

distancetruck=70(t-7)/60 where is in minutes.

at passing, the distances are equal. set them equal and solve for time t.

t=7/6t-49/60

1/6t=49/60

t=4.9 minutes

check my work.

- algebra -
**bobpursley**, Friday, August 26, 2011 at 7:50pmoops, error.

t=7/6 t -49/6

now solve for t

- algebra -
**coursonc**, Sunday, August 28, 2011 at 12:43amI would do it a different way. Since the car has a 7 Min headstart, traveling at 60mph, you can figure the distance it is ahead of the truck. Then, with the truck overtaking the car, by 10mph, you can figure the time it would take, going 10mph to go this headstart distance.

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