a student is selected at is the probability the the randomly selected stundent is neither a 10th grade nor an 11th grade express your answer in fraction in simplest form

Please reread your post. Does it make sense to you? Clarify and repost if you want help.

Also -- what grades are being considered in addition to 10th and 11th?

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FIND 3

TERMS IN GP WHOSE SUM & PRODUCT RESPECTIVELY ARE 28 AND 512

To find the probability that a randomly selected student is neither a 10th grader nor an 11th grader, you first need to know the total number of possible outcomes (i.e., the total number of students).

Let's assume that you have data on the number of students in each grade level. Let's say there are 100 students in total, with 20 students in 10th grade, 30 students in 11th grade, and the remaining (100 - 20 - 30) = 50 students in other grades.

To find the probability, you divide the number of favorable outcomes (students who are neither in 10th nor 11th grade) by the total number of possible outcomes (total number of students).

Favorable outcomes = Number of students in other grades = 50
Total number of students = 100

P(neither 10th nor 11th grade) = Favorable outcomes / Total number of students
P(neither 10th nor 11th grade) = 50 / 100
P(neither 10th nor 11th grade) = 1/2

So, the probability that a randomly selected student is neither a 10th grader nor an 11th grader is 1/2.