Post a New Question

Math

posted by on .

A contractor requires a cement mix that is 70% sand and 30% cement.
He has 700 kg of a cement mix that is 80% sand and 20% cement.
How much cement should he add so that he gets the required mix?


My set up:

required mix = (S)(.7) + (C)(3)

700kg = (S)(.8) + (C+X)(.2)

Is this even correct?

  • Math - ,

    C / (S+c) = 0.3.

    C = 0.8 * 700kg = 560kg.

    C / (560+C) = 0.3,
    C = 168 + .3C,
    C - 0.3C = 168,
    0.7C = 168,
    C = 240kg.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question