A ladder that is 12,5m long rests against a wall with its foot 7,5m away from the wall.How far the ladder reaches up the wall?
Use the Pythagorean Theorem and solve for b.
a^2 + b^2 = c^2
7.5^2 + b^2 = 12.5^2
56.25 + b^2 = 156.25
b^2 = 156.25 - 56.25
b^2 = 100
b = 10
The foot of the ladder in 4.2 above moves 4m closer to the wall.How much further will the ladder now reach up the wall?
Use the Pythagorean theorem as I showed you above.
Thank you
You're welcome.
To determine how far the ladder reaches up the wall, we can use the Pythagorean theorem. The theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the ladder acts as the hypotenuse, the distance from the foot of the ladder to the wall is one of the other sides, and the distance the ladder reaches up the wall is the remaining side. Let's call the distance the ladder reaches up the wall "h."
According to the Pythagorean theorem, we have:
(ladder length)^2 = (distance to the wall)^2 + (distance up the wall)^2
Substituting the given values:
(12.5)^2 = (7.5)^2 + h^2
156.25 = 56.25 + h^2
Subtracting 56.25 from both sides:
100 = h^2
Taking the square root of both sides:
√100 = √(h^2)
10 = h
Therefore, the ladder reaches up the wall to a height of 10 meters.