(3x+8)4 = (10x-7)+(10x-1)
(3x+8)4 = (10x-7)+(10x-1)
12x + 32 = 20x - 8
32 + 8 = 20x - 12x
40 = 8x
? = x
thank you so much i had the 12x+32 part but i didn't know how to do the next part
You're very welcome.
To solve the equation (3x+8)4 = (10x-7)+(10x-1), you need to simplify both sides and combine like terms.
Let's start with the left side of the equation, (3x+8)4:
To simplify this, you need to distribute the 4 to each term inside the parentheses:
(3x+8)4 = 3x(4) + 8(4) = 12x + 32
Now let's simplify the right side of the equation, (10x-7)+(10x-1):
To simplify this, you need to combine like terms. Since both terms have an x, you can combine them:
(10x-7)+(10x-1) = 10x + 10x - 7 - 1 = 20x - 8
Now that both sides of the equation are simplified, we can rewrite the equation as:
12x + 32 = 20x - 8
To solve for x, you need to isolate the x term on one side of the equation. Let's move the 12x term to the right side:
12x + 32 - 12x = 20x - 8 - 12x
32 = 8x - 8
Next, let's move the constant term -8 to the right side:
32 + 8 = 8x - 8 + 8
40 = 8x
To solve for x, divide both sides of the equation by 8:
40/8 = 8x/8
5 = x
Therefore, the solution to the equation (3x+8)4 = (10x-7)+(10x-1) is x = 5.