Precalculus
posted by Jason .
find any intercepts of the graph of the given equation. determine whether the graph of the equation possesses symmetry with respect to the xaxis, yaxis, or orgin
y=x^22x2

y = (x1)^2 3
When y = 0, (x1)^2 = 3
x  1 = + or  sqrt3
x = 1 + sqrt3 or 1  sqrt3
When x = 0, y = 3
There is no symmetry about the x or y axes, or origin. 
When x = 0, y = 2, y axis intercept
When y = 0
x = [ 2 +/ sqrt(4+8)]/2 = 1 +/ sqrt 3
therefore parabola is symmetric about the vertical line x = 1
show it by completing the square
x^2  2x = y + 2
x^2  2x + 1 = y+3
(x1)^2 = (y+3)
vertex at (1,3) 
thank you damon! that was exactly what i was looking for, by the way it's 4:32 am here and i've been searching for that answer for hours...