Posted by Jason on Thursday, August 25, 2011 at 7:11am.
y = (x-1)^2 -3
When y = 0, (x-1)^2 = 3
x - 1 = + or - sqrt3
x = 1 + sqrt3 or 1 - sqrt3
When x = 0, y = -3
There is no symmetry about the x or y axes, or origin.
When x = 0, y = -2, y axis intercept
When y = 0
x = [ 2 +/- sqrt(4+8)]/2 = 1 +/- sqrt 3
therefore parabola is symmetric about the vertical line x = 1
show it by completing the square
x^2 - 2x = y + 2
x^2 - 2x + 1 = y+3
(x-1)^2 = (y+3)
vertex at (1,-3)
thank you damon! that was exactly what i was looking for, by the way it's 4:32 am here and i've been searching for that answer for hours...
Related Questions
Precalculus - find any intercepts of the graph of the given equation. determine ...
Precalculus - find any intercepts of the graph of the given equation. determine...
symmetry help - find any intercepts of the graph of the given equation. ...
math-please help,need quickly - find the slant asymptote of the graphof the ...
math, algebra,graphs help - THe directions state: (A)Complete the table, (B) ...
Algebra - graph the equation x-3=y (where do I plot the points?) find the ...
Intermediate Algebra - For the quadratic equation y=(x-3)^2-2. Determine: A) ...
Intermediate Algebra - For the quadratic equation y=(x-3)^2-2. Determine: A) ...
algebra - y=2x^2+5x-3 a)determine the x-intercepts b)determine the vertex c)...
College Algebra - 1.Answer the following for the given quadratic function. f(x...
For Further Reading
