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December 18, 2014

December 18, 2014

Posted by **Jason** on Thursday, August 25, 2011 at 7:11am.

y=x^2-2x-2

- Precalculus -
**drwls**, Thursday, August 25, 2011 at 7:19amy = (x-1)^2 -3

When y = 0, (x-1)^2 = 3

x - 1 = + or - sqrt3

x = 1 + sqrt3 or 1 - sqrt3

When x = 0, y = -3

There is no symmetry about the x or y axes, or origin.

- Precalculus -
**Damon**, Thursday, August 25, 2011 at 7:24amWhen x = 0, y = -2, y axis intercept

When y = 0

x = [ 2 +/- sqrt(4+8)]/2 = 1 +/- sqrt 3

therefore parabola is symmetric about the vertical line x = 1

show it by completing the square

x^2 - 2x = y + 2

x^2 - 2x + 1 = y+3

(x-1)^2 = (y+3)

vertex at (1,-3)

- Precalculus -
**Jason**, Thursday, August 25, 2011 at 7:32amthank you damon! that was exactly what i was looking for, by the way it's 4:32 am here and i've been searching for that answer for hours...

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