Tuesday
July 22, 2014

Homework Help: Physics

Posted by Kyle on Thursday, August 25, 2011 at 5:09am.

A ball is thrown straight up in the air and passes a window 0.30s after being released. It takes 1.5s to go from the window to its maximum height and back down to the window. What was the initial velocity of the ball when it was released?

I found where the ball would be after 0.30s:

Y = V_0 (0.30) - 1/2 (9.8) (0.30)^2
Y = (0.3) (V_0) - 0.441

Then I found where the ball would be after 1.5 which I took to the be same place as the top equation because it returns to the window:

Y = (0.30*V_0) (1.5) - 1/2 (9.8) (1.5)^2
Y = (0.45) (V_0) - 11.025

then I set the equations together and worked it out to get:
V_0 = 70.56 m/s

Is this correct?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

math - Your friend is standing below the window outside of our classroom and ...
physics - A ball thrown straight up from the ground passes a window 5.6 m up. An...
Physics/Science #3 - A ball is thrown vertically downward from the top of a 35.9...
science - A ball is throen vertically downward from the rop of a 36.6 m tall ...
Physics - A ball is thrown vertically upward from a window with an initial ...
physical - A ball is thrown from the window of a high-rise building with an ...
phy - A ball is thrown from the window of a high-rise building with an initial ...
Physics - A girl notices a ball moving straight upward just outside her window. ...
Physics - A child tosses a baseball to his siter, who is hanging out the window ...
Physics AP - A ball is thrown straight upward with a speed of +12 m/s. A) what's...

Search
Members