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AP Chem

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An ore contains Fe3O4 and no other iron. The iron in a 51-gram sample of the ore is all converted by a series of chemical reactions to Fe2O3. The mass of Fe2O3 is measured to be 21.9 g. What was the mass of Fe3O4 in the
sample of ore?

  • AP Chem - ,

    The simple way is to convert mass Fe2O3 into mass Fe3O4 by using a chemical factor (which is not taught anymore).
    mass Fe2O3 x (2*molar mass Fe3O4/3*molar mass Fe2O3) = ??

  • AP Chem - ,

    I got 156.356 grams, but it still says that's wrong.

  • AP Chem - ,

    I wonder how you obtained that? Post your work. I don't have anything close to that.

  • AP Chem - ,

    21.9 x (463.07/479.07)=21.1685
    Must have done something wrong the first time. Is that right?

  • AP Chem - ,

    Looks ok to me. Now round off to three s.f.

  • AP Chem - ,

    how is the 51 gram sample integrated into the equation then? or is it not used at all in this case?

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