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March 27, 2017

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A drag racer, starting from rest, speeds up for 402 m with an acceleration of +16.0 m/s2. A parachute then opens, slowing the car down with an acceleration of -5.60 m/s2. How fast is the racer moving 2.90 102 m after the parachute opens?

  • phsics - ,

    Vf^2 = Vo^2 + 2ad.

    Vf^2 = 0 + 2*16*402 = 12,864,
    Vf = 113.4m/s.

    Vf^2 = (113.4)^2 + 2*(-5.6)*290 = 9616,
    Vf = 98m/s.

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