Homework Help: phsics

Posted by Paul on Tuesday, August 23, 2011 at 7:23pm.

A drag racer, starting from rest, speeds up for 402 m with an acceleration of +16.0 m/s2. A parachute then opens, slowing the car down with an acceleration of -5.60 m/s2. How fast is the racer moving 2.90 102 m after the parachute opens?

phsics - Henry, Wednesday, August 24, 2011 at 2:50pm
Vf^2 = Vo^2 + 2ad.

Vf^2 = 0 + 2*16*402 = 12,864,
Vf = 113.4m/s.

Vf^2 = (113.4)^2 + 2*(-5.6)*290 = 9616,
Vf = 98m/s.

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