Posted by marie s on Tuesday, August 23, 2011 at 6:10pm.
a political discussion group consists of five Democrats and six Republicans. Four people are selected to attend a conference.
A.in how many ways can four people be selected from this group of eleven?
B.In how many ways can four Republicans be selected from six Republicans?
C.find the probability that the selected group will consist of all Republicans?
- math - deja, Tuesday, August 23, 2011 at 6:19pm
the answer is "C"
- math - marie s, Tuesday, August 23, 2011 at 6:21pm
Thanks, but i need the answer to all three questions
- math - Reiny, Tuesday, August 23, 2011 at 6:23pm
A) choose 4 from 11 which is C(11,4) or 330
b) choose 4 from 6 which is C(6,4) or 15
c) assuming that your group still consists of 4 people
prob = 15/330 = 1/22
- math - marie s, Tuesday, August 23, 2011 at 6:24pm
- math - drwls, Tuesday, August 23, 2011 at 6:25pm
A. 11 x 10 x 9 x 8/(4 x 3 x 2 x 1) = 330
B. 6!/(4!*2!) = 15
C. (6/11)*(5/10)*(4/9)*(3/8) = 0.04545
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