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April 19, 2014

April 19, 2014

Posted by **marie s** on Tuesday, August 23, 2011 at 6:10pm.

A.in how many ways can four people be selected from this group of eleven?

B.In how many ways can four Republicans be selected from six Republicans?

C.find the probability that the selected group will consist of all Republicans?

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**deja**, Tuesday, August 23, 2011 at 6:19pmthe answer is "C"

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**marie s**, Tuesday, August 23, 2011 at 6:21pmThanks, but i need the answer to all three questions

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**Reiny**, Tuesday, August 23, 2011 at 6:23pmA) choose 4 from 11 which is C(11,4) or 330

b) choose 4 from 6 which is C(6,4) or 15

c) assuming that your group still consists of 4 people

prob = 15/330 = 1/22

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**marie s**, Tuesday, August 23, 2011 at 6:24pmthank you

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**drwls**, Tuesday, August 23, 2011 at 6:25pmA. 11 x 10 x 9 x 8/(4 x 3 x 2 x 1) = 330

B. 6!/(4!*2!) = 15

C. (6/11)*(5/10)*(4/9)*(3/8) = 0.04545

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