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November 28, 2014

November 28, 2014

Posted by **sarah** on Tuesday, August 23, 2011 at 3:54pm.

10. Divide (3x – 2)(x - 4) – (x - 4)(6 – 5x) / (4 – x)(8x – 1)

10- (3x-2)(x-4)-(x-4)(6-5x)/(4-x)(8x-1)

The (x-4) cancels out because the (x-4)is common in all the terms of the top and bottom

[(3x-2)]-[(6-5x)]/-(8x-1)

3x+5x=8x

-2-(-6)=-8

8x-8/-(8x-1)

8x-8 factored = 8(x-1)

8(x-1)/-(8x-1) = -1+7/8x-1

- algbra -
**Reiny**, Tuesday, August 23, 2011 at 5:02pmPicking up from

[(3x-2)]-[(6-5x)]/-(8x-1) , which is correct up to there

= (8x - 8)/(1-8x)

= 8(x-1)/(1-8x)

nothing else can be done

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