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algbra

posted by on .

i was wondering what did i do wrong in this
10. Divide (3x – 2)(x - 4) – (x - 4)(6 – 5x) / (4 – x)(8x – 1)

10- (3x-2)(x-4)-(x-4)(6-5x)/(4-x)(8x-1)

The (x-4) cancels out because the (x-4)is common in all the terms of the top and bottom

[(3x-2)]-[(6-5x)]/-(8x-1)

3x+5x=8x
-2-(-6)=-8

8x-8/-(8x-1)

8x-8 factored = 8(x-1)

8(x-1)/-(8x-1) = -1+7/8x-1

  • algbra - ,

    Picking up from
    [(3x-2)]-[(6-5x)]/-(8x-1) , which is correct up to there
    = (8x - 8)/(1-8x)
    = 8(x-1)/(1-8x)

    nothing else can be done

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