Posted by sarah on .
i was wondering what did i do wrong in this
10. Divide (3x – 2)(x  4) – (x  4)(6 – 5x) / (4 – x)(8x – 1)
10 (3x2)(x4)(x4)(65x)/(4x)(8x1)
The (x4) cancels out because the (x4)is common in all the terms of the top and bottom
[(3x2)][(65x)]/(8x1)
3x+5x=8x
2(6)=8
8x8/(8x1)
8x8 factored = 8(x1)
8(x1)/(8x1) = 1+7/8x1

algbra 
Reiny,
Picking up from
[(3x2)][(65x)]/(8x1) , which is correct up to there
= (8x  8)/(18x)
= 8(x1)/(18x)
nothing else can be done