calculate the number of moles of sodium carbonate in one dm3
do you mean density of Na2CO3 of 1 dm^3 volume? if so, we first find its density. Since sodium carbonate only, assume that it is anhydrous (no water/hydrate). from density data found in some books, density of Na2CO3 is 2.54 g/cm^3.
then we get the corresponding mass for a volume of 1 dm^3. note that 1 dm^3 = 1000 cm^3, thus,
m = 2.54 g/cm^3 * 1000 cm^3 = 2540 g Na2CO3
then we calculate its molar mass. we get the masses of each element (Na, C and O) from periodic table:
Na = 23 , C = 12 , O = 16
mass of Na2CO3 = 2*23 + 12 + 3*16 = 106 g/mol
finally, we get the number of moles by dividing the given/calculated mass (the 2540 g) by the molar mass:
2540/106 = 23.9623 mol Na2CO3
hope this helps~ :)
To calculate the number of moles of sodium carbonate in one dm3, you will need the molar mass of sodium carbonate and the concentration of the solution.
1. Find the molar mass of sodium carbonate (Na2CO3).
- Sodium (Na) has a molar mass of 22.99 g/mol.
- Carbon (C) has a molar mass of 12.01 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
- Sodium carbonate contains 2 sodium atoms, 1 carbon atom, and 3 oxygen atoms.
Molar mass of Na2CO3 = (2 * 22.99 g/mol) + (1 * 12.01 g/mol) + (3 * 16.00 g/mol) = 105.99 g/mol.
2. Determine the concentration of the solution in moles per dm3 (Molarity, M).
- Assuming the solution is a standard solution, which means it is made in a way that 1 dm3 of solution contains one mole of sodium carbonate.
- Hence, the concentration is 1 mole/dm3 or 1 M.
Therefore, the number of moles of sodium carbonate in one dm3 is 1 mol.