Question

Iam re-posting the following questions and would appreciate if anyone could show the working.

1]Find lim sinx/2x
x-->0

2]lim 3x^2-4x/7
x-->0

Answer 1

lim sinx/(2x) as x --> 0

= lim (1/2) sinx/x
= (1/2)(0) = 0

2. lim 3x^2 - 4x/7 as x --->0
= 0 - 0/7 = 0