Angle 3 and angle 4 form a linear pair. The measure of angle 3 is four more than three times the measure of angle 4. Find the measure of each angle.

first we represent the unknowns using variables:

let x = measure of angle 4
let 3x+4 = measure of angle 3 (from the second statement)
then we set-up the equation. since the angles form a linear pair, their sum is equal to 180 degrees. therefore,
x + 3x + 4 = 180
4x + 4 = 180
4x = 176
x = 44 degrees (measure of angle 4)
3x + 4 = 136 degrees (measure of angle 3)

hope this helps~ :)

these equations are hard looking

If \large \angle1 and \large \angle2 are vertical angles, \large \angle2 and \large \angle3 are complementary angles, and m\large \angle3=47, find m\large \angle1=

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To find the measure of each angle, let's first define our variables:

Let x be the measure of angle 4.

Since angle 3 is four more than three times the measure of angle 4, we can represent the measure of angle 3 as 3x + 4.

According to the given information, angle 3 and angle 4 form a linear pair. By definition, a linear pair is formed when two angles are adjacent and the sum of their measures is 180 degrees.

Therefore, we can write an equation based on the linear pair:

angle 3 + angle 4 = 180

Substituting the measures we found:

(3x + 4) + x = 180

Combining like terms:

4x + 4 = 180

Subtracting 4 from both sides:

4x = 176

Dividing both sides by 4:

x = 44

Now that we have the measure of angle 4:

angle 4 = x = 44 degrees

To find the measure of angle 3, substitute the value of x into the expression we derived earlier:

angle 3 = 3x + 4 = 3(44) + 4 = 132 + 4 = 136 degrees

Therefore, the measure of angle 3 is 136 degrees and the measure of angle 4 is 44 degrees.

Ray AB bisects \large \angleCAD. m\large \angleCAB= x+7, m\large \angleBAD= 6x-8.

If \large \angle3 and \large \angle4 form a linear pair, and m\large \angle4=23°, then m\large \angle3=