2=-4+4 square root x^3
I added the four to both sides
divided four
squared
then divided that my cube root
my answer:1.31
x^(3/2) = 6/4 = 3/2
Take the 2/3 power of each side.
x = (3/2)^(2/3)
x = 1.3104.. You are correct
Thank you hon!
To solve the equation: 2 = -4 + 4√x^3, you followed these steps:
1. Start with the equation: 2 = -4 + 4√x^3.
2. Add 4 to both sides of the equation to isolate the square root term: 2 + 4 = -4 + 4 + 4√x^3, which simplifies to 6 = 4 + 4√x^3.
3. Divide both sides of the equation by 4, to get: (6/4) = (4 + 4√x^3)/4. Simplifying this further, we have 3/2 = 1 + √x^3.
4. Square both sides of the equation to eliminate the square root: (3/2)^2 = (1 + √x^3)^2. This becomes 9/4 = (1 + √x^3) * (1 + √x^3).
5. Expand the right side of the equation: 9/4 = 1 + √x^3 + √x^3 + (√x^3)^2. Simplifying, we have 9/4 = 1 + 2√x^3 + x^3.
6. Subtract 1 from both sides of the equation to isolate the terms with the square root and the cube root: 9/4 - 1 = 1 + 2√x^3 + x^3 - 1, which simplifies to 5/4 = 2√x^3 + x^3.
7. Finally, divide both sides of the equation by 2, to get: (5/4)/2 = (2√x^3 + x^3)/2. This gives us 5/8 = √x^3/2 + x^3/2.
Based on the steps you described, it seems like you squared both sides again to further isolate the x^3 term, which would explain why you ended up with x^3/2. Then, you divided by the cube root, which was a deviation from the original equation.
To find x, you would typically continue solving for x using algebraic manipulations. However, it is unclear from your description how you calculated the final value of 1.31.