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March 27, 2015

March 27, 2015

Posted by **lili** on Monday, August 22, 2011 at 6:26pm.

- chemistry -
**DrBob222**, Monday, August 22, 2011 at 8:05pmI solve these limiting reagent problems the long way by solving two simpler stoichiometry problems. Here is a step by step procedure for solving the simple stoichiometry problems.

http://www.jiskha.com/science/chemistry/stoichiometry.html

Solve the first time using moles NaI (moles = M x L) and solve for moles I2 produced. Solve the second time using moles Br2 for moles I2 formed. You have two answers and of course one of them must be wrong. In limiting reagent problems, the smaller value is ALWAYS the correct one to use.

The equation is

2NaI + Br2 ==> 2NaBr + I2.

After finding the theoretical yield from the calculations above, then

theoretical yield x 0.81 = actual yield.

Post your work if you get stuck.

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