Can you help me write these out in an algebraic expression?

1. Seven less than twice a number equals 19.

2.Eight decreased by 3 times a number equals 2.

3. The sum of two times a number and 5 is 11.

Is this right?
x/8 + -1/2 = 6

My answer: x=44

no. Add 1/2 to each side

x/8=6.5
multiply both sides by 8
x=52

Thank you so much! Just redid it, and got it right:) anyways, what about the other questions though?

1. Seven less than twice a number equals 19

2n - 7 = 19

2.Eight decreased by 3 times a number equals 2

8 - 3n = 2

Thank You So Much<3 love you guys.

3. 2n+5=11

Sure! I can help you write these algebraic expressions.

1. "Seven less than twice a number equals 19."
To write this as an algebraic expression, let's assume the number is represented by the variable x. Twice the number is 2x, and seven less than that would be 2x - 7. So the expression is: 2x - 7 = 19.

2. "Eight decreased by 3 times a number equals 2."
Again, let's assume the number is x. Three times the number is 3x, and when you subtract that from eight, you get 8 - 3x. So the expression is: 8 - 3x = 2.

3. "The sum of two times a number and 5 is 11."
Assuming the number is x, two times the number is 2x. The sum of that and 5 would be 2x + 5. So the expression is: 2x + 5 = 11.

Regarding your question about the equation, let's solve it to confirm if your answer is correct.

x/8 - 1/2 = 6

To solve this equation, let's first find a common denominator. The least common multiple of 8 and 2 is 8. So the equation becomes:

(2x - 8) / 8 = 6

Now, let's cross multiply to isolate the variable:

2x - 8 = 48

Next, let's add 8 to both sides of the equation:

2x = 56

Finally, divide both sides by 2:

x = 28

Therefore, based on the solution to the equation, it appears that your answer is incorrect. The correct value for x in this equation is 28, rather than 44.