Let [a b c] be defined by [a b c]= 2ab +3c for all integers a,b, and c. If [x 3 3] = 3, what is the value of x?
[x,3,3]= 3 2.x.3+3.3=3 3[2x+3]=3
2x+3=3/3=1 2x=1-3 2x=-2 x=-2/2 =-1 x=-1
if [a b c} = 2ab + 3c , then
[x 3 3) = 2(x)(3) + 3(3) = 3
6x + 9 = 3
6x = -6
x = -1
To find the value of x, we need to substitute the given values into the expression [a b c] = 2ab + 3c and solve for x.
Given that [x 3 3] = 3, we can substitute x = 3, b = 3, and c = 3 into the expression:
[3 3 3] = 2(3)(3) + 3(3)
Now we simplify the expression:
[3 3 3] = 18 + 9
[3 3 3] = 27
Since [x 3 3] = 3, this implies that x = 3, so the value of x is 3.