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November 28, 2014

November 28, 2014

Posted by **Abel** on Sunday, August 21, 2011 at 4:34pm.

- math -
**bobpursley**, Sunday, August 21, 2011 at 4:38pmalgebraic method?

x+4y=14

3x+2y=12

multipy the first equation by 3

3x+12y=42

3x+2y=12

subtract the second equation from the first.

10y=30

y=3

put that value of y into either equation, and solve for x.

- math -
**dvr**, Monday, August 22, 2011 at 4:31amx=2

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