Posted by Abel on Sunday, August 21, 2011 at 4:34pm.
algebraic method?
x+4y=14
3x+2y=12
multipy the first equation by 3
3x+12y=42
3x+2y=12
subtract the second equation from the first.
10y=30
y=3
put that value of y into either equation, and solve for x.
x=2
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