Posted by Luke Phillips on Sunday, August 21, 2011 at 3:08pm.
The distance between A and B can be calculated using the distance formula:
distance(A,B)=sqrt((xb-xa)^2+(yb-ya)^2)
=sqrt((1-6)^2+(3-10)^2)
=sqrt(25+49)
=sqrt(74)
=8.602 approx.
You can find similarly the distances BC and CA.
Add up the sum AB+BC+CA which is the perimeter of the original triangle.
For the triangle with coordinates 3 times shown, multiply the original perimeter by 3.
Related Questions
Math Geometry - A triangle has vertices P(a,b), Q(c,d), and R(e,f). You are ...
geometry - Triangle PQR has vertices P(1,2), Q(25,2) and R(10,20). Find the ...
MATH - Triangle T has vertices A(-9, 10)B(1,0)and C(5,4). Points A, B, and P(...
Geometry - Determine whether triangle PQR is congruent to triangle STU given the...
Ottawa University - Triangle T has vertices A(-9, 10)B(1,0)and C(5,4). Points A...
Geometry - I need help with vertices! The vertices of triangle FGH are F(1,1), G...
Geometry - Help I need help to find the coordinates of the circumcenter of each...
geometry - The coordinates of the vertices of triangle CDE are C(1,4), D(3,6), ...
analytic geometry - the base of an isoceles triangle lies on the x-axis. The ...
Geometry - Triangle ABC has vertices A = (0,6) B = (-2,3), and C = (2,1). Find ...
For Further Reading
