Posted by **Luke Phillips** on Sunday, August 21, 2011 at 3:08pm.

The coordinates of the vertices of a triangle are A(1,3), B(6,10), and C(11,18). Find the perimeter of the triangle when the coordinates are multiplied by 3.

- geometry -
**MathMate**, Sunday, August 21, 2011 at 3:52pm
The distance between A and B can be calculated using the distance formula:

distance(A,B)=sqrt((xb-xa)^2+(yb-ya)^2)

=sqrt((1-6)^2+(3-10)^2)

=sqrt(25+49)

=sqrt(74)

=8.602 approx.

You can find similarly the distances BC and CA.

Add up the sum AB+BC+CA which is the perimeter of the original triangle.

For the triangle with coordinates 3 times shown, multiply the original perimeter by 3.

## Answer This Question

## Related Questions

- Geometry - I need help with vertices! The vertices of triangle FGH are F(1,1), G...
- geometry - The coordinates of the vertices of triangle CDE are C(1,4), D(3,6), ...
- Geometry - Determine whether triangle PQR is congruent to triangle STU given the...
- analytic geometry - the base of an isoceles triangle lies on the x-axis. The ...
- geometry - Triangle PQR has vertices P(1,2), Q(25,2) and R(10,20). Find the ...
- math - A triangle has vertices with coordinates (2, 0), (3, -1), and (-2, -5). ...
- math - A triangle has vertices with coordinates (2, 0), (3, -1), and (-2, -5). ...
- Math - A triangle is graphed in the coordinate plane. The vertices of the ...
- Math Geometry - A triangle has vertices P(a,b), Q(c,d), and R(e,f). You are ...
- Geometry - Triangle ABC has vertices of A(0,0), B(–4,0)and C(–2,4). The ...

More Related Questions