the velocity of a car increases from 36km/hr to 54km/hr in one minute determine the force exerted by the engine on the car mass of the car is 120kg
First convert those two speeds to m/s.
Then compute the acceleration,
a = (V2 - V1)/60 s, in units if m/s^2
Then use F = M a for the accelerating force in Newtons.
The force exerted by the engine is actually higher thn that because there is a backwards air resistance force.
10 newton.
To determine the force exerted by the engine on the car, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a). In this case, we need to calculate the acceleration.
First, let's convert the initial and final velocities from km/hr to m/s by dividing by 3.6 (since 1 km/hr = 1/3.6 m/s).
Initial velocity (u) = 36 km/hr = (36/3.6) m/s = 10 m/s
Final velocity (v) = 54 km/hr = (54/3.6) m/s = 15 m/s
Next, we can calculate the acceleration (a) using the formula:
a = (v - u) / t,
where (v - u) is the change in velocity and t is the time interval in seconds. In this case, the time interval is given as 1 minute, which is equal to 60 seconds.
Therefore, a = (15 - 10) m/s / 60 s = 0.0833 m/s^2.
Finally, we can calculate the force (F) exerted by the engine using the formula:
F = m * a,
where m is the mass of the car given as 120 kg.
Hence, F = 120 kg * 0.0833 m/s^2 = 9.996 N (approximately equal to 10 N)
Therefore, the force exerted by the engine on the car is approximately 10 Newtons.