Posted by ahsan asghar on Sunday, August 21, 2011 at 3:47am.
ans (3.608m,3.388m\sec)
a stone is dropped from the top of a tower .in the last second of its motion it travels a distance of 44,1m.find(a)height of tower .(b)velocity while hitting the ground.
a stone is dropped from the top of a tower .in the last second of its motion it travels a distance of 44,1m.find(a)height of tower .(b)velocity while hitting the ground.
Let H be the tower heiight and g the acceleration of gravity (9.8 m/s^2). Let t be the time it takes to fall the full tower height. Here is what you know:
H = (g/2) t^2
H-44.1 = (g/2)(t-1)^2
Solve those two equations TOGETHER for the height H. It is easiest to solve for t first
44.1 = (g/2)*[t^2 - t^2 + 2t -1)
= 4.9 [2t - 1)
2t -1 = 9
t = 5 seconds
H = 4.9*25 = 122.5 m
(b) Vfinal^2 = 2 g H
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