a ball is dropped from the height. if it takes 0.2 sec. to cross the last 6 m before hitting the ground find the ht. from which it was dropped

(Time to reach ground) - (Time to reach 6 m above ground) = 0.2 s

sqrt(2H/g) - sqrt[2(H-6)/g] = 0.2

Let g = 9.8 m/s^2 and solve for H

0.4517[sqrtH - sqrt(H-6)] = 0.2
sqrtH - sqrt(H-6) = 0.4427

H = 49 m

To find the height from which the ball was dropped, we can use the equations of motion.

First, let's determine the initial velocity of the ball when it was dropped.

We know that the time it takes for the ball to cross the last 6m is 0.2 seconds. In this time, the vertical displacement of the ball must be the last 6m before hitting the ground.

Using the equation of motion for vertical displacement (s = ut + 0.5 * a * t^2), where s is the displacement, u is the initial velocity, a is the acceleration (which is due to gravity and equal to -9.8 m/s^2 for objects near the Earth's surface), and t is the time, we can plug in the values we have:

s = -6m (taking downward direction as negative)
a = -9.8 m/s^2
t = 0.2s

-6 = u * 0.2 + 0.5 * (-9.8) * (0.2)^2

Simplifying this equation, we get:

-6 = 0.2u - 0.196

Rearranging the equation to solve for u, we get:

0.2u = -6 + 0.196
0.2u = -5.804

u = -5.804 / 0.2
u ≈ -29.02 m/s

The negative sign indicates that the initial velocity is in the downward direction, which is expected since the ball is dropped.

Now, let's calculate the height from which the ball was dropped using the equation of motion for displacement (s = ut + 0.5 * a * t^2).

Taking the final displacement (s) to be 0 (since the ball hits the ground), u = -29.02 m/s, and a = -9.8 m/s^2, we can plug in these values and solve for the initial displacement:

0 = -29.02 * t + 0.5 * (-9.8) * t^2

0 = -29.02 * t - 4.9 * t^2

We know that the initial displacement is equal to the height from which the ball was dropped. Rearranging the equation, we have:

4.9 * t^2 = -29.02 * t

Dividing both sides by t:

4.9t = -29.02

t ≈ -29.02 / 4.9
t ≈ -5.93 (approximately)

Since time cannot be negative, this result seems invalid. It suggests that we made a mistake in the calculations or the given information. Please check the values and ensure all the details are accurate.