Write the following without negative exponents: (a^-1 + b^-1)^-1

(a^-1 + b^-1)^-1

= (1/a + 1/b)^-1
=((b+a)/(ab))^-1
= (ab)/(a+b)

(1/a + 1/b)^-1 = 1 / (1/a + 1/b).

To write the expression (a^-1 + b^-1)^-1 without negative exponents, we can make use of the exponent properties.

First, let's rewrite the expression with positive exponents:

(a^-1 + b^-1)^-1

Using the property that a^-m = 1/a^m, we can rewrite the exponents so that they become positive:

(1/a + 1/b)^-1

Next, we need to evaluate the expression inside the parentheses by finding a common denominator for a and b. The common denominator is ab, so we can rewrite 1/a and 1/b with a common denominator:

(1/a + 1/b)^-1 = (b/ab + a/ab)^-1

Notice that we have a common denominator of ab now. We can combine the terms inside the parentheses:

= (b + a)/(ab)^-1
= (b + a)/(1/ab)

Finally, to simplify further, we can multiply the numerator and denominator by ab:

= (b + a)(ab)/(1)
= ab(b + a)

So, without negative exponents, the expression (a^-1 + b^-1)^-1 simplifies to ab(b + a).