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Posted by on Friday, August 19, 2011 at 3:44pm.

an antique dealer visited three shops.she spent 25$ at the first shop.at the second shop she spent half of her remaining money .at the third shop she spent one third of her remaining money and had 60$ left.How much money did the dealer have originally?

  • math - , Saturday, August 20, 2011 at 12:48pm

    Let x = original money

    x - 25 - .5(x-25) - [.5(x-25)]/3 = 60

    Solve for x.

  • math - , Saturday, August 20, 2011 at 2:34pm

    Original Amt. = $X.

    1. Spent: $25.
    Bal. = (X-25).

    2. Spent: (X-25)/2.
    Bal. = (X-25)/2.

    3. Spent: (1/3)(X-25)/2 = (x-25)/6.
    Bal. = (X-25)/2 - (x-25)/6,
    Bal.=3(X-25)/6 - (X-25)/6 = 2(X-25)/6 =
    (X-25)/3.

    Bal. = (X-25)/3 = $60.
    (X-25)/3 = 60,
    Multiply both sides by 3:
    X - 25 = 180,
    X = 180 + 25 = $205. = Original Amt.

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