Posted by **lisa** on Friday, August 19, 2011 at 3:44pm.

an antique dealer visited three shops.she spent 25$ at the first shop.at the second shop she spent half of her remaining money .at the third shop she spent one third of her remaining money and had 60$ left.How much money did the dealer have originally?

- math -
**PsyDAG**, Saturday, August 20, 2011 at 12:48pm
Let x = original money

x - 25 - .5(x-25) - [.5(x-25)]/3 = 60

Solve for x.

- math -
**Henry**, Saturday, August 20, 2011 at 2:34pm
Original Amt. = $X.

1. Spent: $25.

Bal. = (X-25).

2. Spent: (X-25)/2.

Bal. = (X-25)/2.

3. Spent: (1/3)(X-25)/2 = (x-25)/6.

Bal. = (X-25)/2 - (x-25)/6,

Bal.=3(X-25)/6 - (X-25)/6 = 2(X-25)/6 =

(X-25)/3.

Bal. = (X-25)/3 = $60.

(X-25)/3 = 60,

Multiply both sides by 3:

X - 25 = 180,

X = 180 + 25 = $205. = Original Amt.

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