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Posted by on Friday, August 19, 2011 at 2:23pm.

Find the area of the sector of the disk of radius r=15 ft and with arc length s=13 ft.

When I did it it came out to .8666667, is that right or do I have to do 1/(13)(15) to get 1.15384571.

  • Math - , Friday, August 19, 2011 at 4:15pm

    circumference = 2P(15) = 30π
    fraction of arc over circumference = 13/30π = .137934

    whole area = P(15^2) = 225π

    sector = .137934(225π) = 97.5 ft^2

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