Tuesday

November 25, 2014

November 25, 2014

Posted by **Cinderella** on Thursday, August 18, 2011 at 10:52pm.

Here how I started it:

x^2-6x+9=-8y+31

Im not sure what to do from here :(

- Precalc -
**Anonymous**, Friday, August 19, 2011 at 1:24amIf x^2-6x+8y-31 mean:

x^2-6x+8y-31=0 then

8y= -x^2+6x+31 Divide with 8

y= -x^2/8 + 6x/8 + 31/8

y= -x^2/8 + 3x/4 + 31/8

**Answer this Question**

**Related Questions**

Pre-Cal - I'm trying to put this parabola in standard form which is: (y-k)^2=4p(...

Parabola - How do I put this parabola in standard form? Could someone show how ...

algebra - Suppose a parabola has a vertex (-4,7) and also passes through the ...

Algebra - I know that standard form is Ax+By=C, but I'm not really sure how to ...

precalc - Parabola: Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work...

Algebra 2 - I have a question and I can not figure it out. Any answers to the ...

Pre-Calc - Here I am again stuck with another geometry type question. Here goes...

precalculus - Find an equation for the parabola that has its vertex at the ...

Algebra 1 parabola's - I have a graph with a parabola on it and asked to write ...

Alg II/Trig - A parabola has a vertex at (0,0); a horizontal axis; and the point...