2. The Sugar Sweet Company is going to transport its sugar to market. It will cost $4200 to rent trucks, and it will cost an additional $150 for each ton of sugar transported. Let C represent the total cost (in dollars), and Let S represent the amount of sugar (in tons) transported. Write an equation relating C to S, and then graph your equation using the axes below.

The equation relating the total cost (C) to the amount of sugar transported (S) can be written as:

C = 4200 + 150S

To graph this equation, we can plot points and draw a line.

Let's choose a few values for S and calculate the corresponding values of C:

When S = 0, C = 4200 + 150(0) = 4200
When S = 1, C = 4200 + 150(1) = 4350
When S = 2, C = 4200 + 150(2) = 4500
When S = 3, C = 4200 + 150(3) = 4650

Now we can plot these points on a graph:

- Plot (0, 4200)
- Plot (1, 4350)
- Plot (2, 4500)
- Plot (3, 4650)

Once we have these points, we can connect them with a straight line:

Now, let's draw the graph.

To write an equation relating the total cost (C) to the amount of sugar transported (S), we need to consider two components: the fixed cost of renting trucks and the variable cost based on the amount of sugar.

The fixed cost of renting trucks is given as $4200. This cost remains the same regardless of the amount of sugar transported. Therefore, it can be represented as a constant term.

The variable cost is $150 for each ton of sugar transported. This cost increases linearly with the amount of sugar. So, we can express this part as the product of the variable cost per ton ($150) and the amount of sugar (S).

Combining these two components, we can write the equation as follows:

C = 4200 + 150S

Now, let's graph this equation using the axes below.

Assuming the horizontal axis represents the amount of sugar transported (S) and the vertical axis represents the total cost (C), we can plot several points on the graph and connect them to visualize the relationship.

To make it easier, let's choose some values for S and calculate the corresponding C. We can start with S = 0, 1, 2, 3, and so on.

When S = 0:
C = 4200 + 150 * 0 = 4200
So, one point on the graph is (0, 4200).

When S = 1:
C = 4200 + 150 * 1 = 4350
Another point on the graph is (1, 4350).

Similarly, we can calculate more points for different values of S. Once we have enough points, we can plot them on the graph and connect them with a straight line.

(Note: I'm sorry, but as a text-based AI bot, I can't physically draw a graph here. However, you can easily plot the points on a piece of paper or using any graphing software to visualize the relationship between the total cost and the amount of sugar transported.)

C = 150S + 4200.